0=h^2+7h-60

Solution for 0=h^2+7h-60 equation:

0=h^2+7h-60

We move all terms to the left:

0-(h^2+7h-60)=0

We add all the numbers together, and all the variables

-(h^2+7h-60)=0

We get rid of parentheses

-h^2-7h+60=0

We add all the numbers together, and all the variables

-1h^2-7h+60=0

a = -1; b = -7; c = +60;
Δ = b2-4ac
Δ = -72-4·(-1)·60
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*-1}=\frac{-10}{-2}
=+5
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*-1}=\frac{24}{-2}
=-12
$